Center of Mass of Equilateral Triangle
3D visualization of the center of mass calculation for three particles
Particle Positions: O(0,0), A(0.5,0), B(0.25,0.25√3)
Particle Masses: O: 100g, A: 150g, B: 200g
Center of Mass Calculation
X = [100(0) + 150(0.5) + 200(0.25)] / (100 + 150 + 200) = 125/450 = 5/18 m
Y = [100(0) + 150(0) + 200(0.25√3)] / (100 + 150 + 200) = 50√3/450 = √3/9 m
Result: Center of mass is at (5/18, √3/9) meters
The system consists of three particles at the vertices of an equilateral triangle with side length 0.5m. The center of mass is calculated as the weighted average of their positions.
Note that the center of mass is not the geometric center of the triangle. Can you explain why?
