Car-Spring Collision Simulation
This simulation demonstrates the conversion of kinetic energy to spring potential energy during a collision, based on Example 6.8 from the textbook. Observe how the car's kinetic energy transforms into spring potential energy upon impact.
Speed: 5.0 m/s
Car Mass
1000 kg
Initial Speed
18 km/h (5 m/s)
Spring Constant
6.25 × 10³ N/m
Spring Compression
0.00 m
Kinetic Energy
12500 J
Spring Energy
0 J
0%
25%
50%
75%
100%
Kinetic Energy (K)
Spring Potential Energy (V)
Total Mechanical Energy (E)
Physics Explanation:
From the textbook example with a 1000 kg car moving at 18 km/h (5 m/s) and spring constant k = 6.25 × 10³ N/m:
Initial kinetic energy of car:
K = ½mv² = ½ × 1000 kg × (5 m/s)² = 12500 J
K = ½mv² = ½ × 1000 kg × (5 m/s)² = 12500 J
At maximum compression (xm):
All kinetic energy converts to spring potential energy:
V = ½kxm² = K
xm = √(2K/k) = √(2 × 12500 / 6250) = 2 m
All kinetic energy converts to spring potential energy:
V = ½kxm² = K
xm = √(2K/k) = √(2 × 12500 / 6250) = 2 m
The simulation shows how the car's kinetic energy is gradually converted to the spring's potential energy during the collision, with the total mechanical energy remaining constant (conservation of energy).
Conservation of Energy:
E = K + V = constant
At any point during collision: ½mv² + ½kx² = ½mv₀²
E = K + V = constant
At any point during collision: ½mv² + ½kx² = ½mv₀²