3D Billiard Ball Collision Physics
This 3D simulation demonstrates the 53° angle needed for a billiard player to sink the target ball at 37° after an elastic collision.
53°
Target Angle: 37°
Collision Type: Elastic
Success: -
Physics Explanation:
For an elastic collision between equal mass billiard balls:
Momentum conservation:
v₁ᵢ = v₁f + v₂f
Energy conservation:
v₁ᵢ² = v₁f² + v₂f²
Combining these gives:
cos(θ₁ + θ₂) = 0 ⇒ θ₁ + θ₂ = 90°
For θ₂ = 37° (corner pocket):
θ₁ = 90° - 37° = 53°
v₁ᵢ = v₁f + v₂f
Energy conservation:
v₁ᵢ² = v₁f² + v₂f²
Combining these gives:
cos(θ₁ + θ₂) = 0 ⇒ θ₁ + θ₂ = 90°
For θ₂ = 37° (corner pocket):
θ₁ = 90° - 37° = 53°
The cue ball must strike the target ball at 53° to send it toward the pocket at 37°.