Billiard Ball Collision with Wall

Billiard Ball Collision with Wall

Understanding forces and impulses during collisions

Theory

Two identical billiard balls strike a rigid wall with the same speed but at different angles, and get reflected without any change in speed. We examine:

  1. The direction of the force on the wall due to each ball
  2. The ratio of the magnitudes of impulses imparted to the balls by the wall

Key Concepts:

1. The force on the wall is always normal (perpendicular) to the wall, regardless of the ball's approach angle.

2. Impulse equals change in momentum: \( \vec{J} = \Delta\vec{p} = m\Delta\vec{v} \)

3. Newton's Third Law: Force on wall = -Force on ball

Case (a) - Normal incidence:

Initial momentum: \( p_x = mu \), \( p_y = 0 \)

Final momentum: \( p_x = -mu \), \( p_y = 0 \)

Impulse: \( J_x = -2mu \), \( J_y = 0 \)

Case (b) - 30° incidence:

Initial momentum: \( p_x = mu\cos30° \), \( p_y = mu\sin30° \)

Final momentum: \( p_x = -mu\cos30° \), \( p_y = mu\sin30° \)

Impulse: \( J_x = -2mu\cos30° \), \( J_y = 0 \)

Impulse ratio: \( \frac{J_a}{J_b} = \frac{2mu}{2mu\cos30°} = \frac{1}{\cos30°} = \frac{2}{\sqrt{3}} \)

Interactive Simulation

Ball Speed
u
Case (a) Impulse
2mu ←
Case (b) Impulse
2mu cos30° ←
Impulse Ratio
2/√3 ≈ 1.15
Case (a) - Normal Incidence
Case (b) - 30° Incidence

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