Capacitive Reactance Simulation
Example 7.4: Capacitor in AC Circuit
A 15.0 μF capacitor is connected to a 220 V, 50 Hz source. Find the capacitive reactance and the current (rms and peak) in the circuit. If the frequency is doubled, what happens to the capacitive reactance and the current?
AC
0
Irms
Ipeak
220 V
50 Hz
15.0 μF
Voltage Waveform
Current Waveform (leading by 90°)
Calculated Values:
Capacitive Reactance (XC) = 1/(2πνC) = 1/(2 × 3.14 × 50 × 15 × 10-6) = 212.21 Ω
RMS Current (Irms) = V/XC = 220 / 212.21 = 1.04 A
Peak Current (Ipeak) = Irms × √2 = 1.04 × 1.414 = 1.47 A
