Inductive Reactance and Bulb Brightness

Inductive Reactance and Bulb Brightness

This simulation demonstrates how inserting an iron rod into an inductor affects a light bulb's brightness in an AC circuit, as described in Example 7.5.

AC Source Key Light Bulb Inductor
Bulb Brightness

Inductance (L)

0.1 H

Without iron core

Inductive Reactance (XL)

31.4 Ω

XL = 2πfL

Bulb Voltage

110 V

Vbulb = Vsource × (Rbulb/Z)

Inductor Voltage

110 V

VL = Vsource × (XL/Z)

Explanation (from Example 7.5):

When an iron rod is inserted into the inductor:

  • The magnetic field inside the coil increases, magnetizing the iron
  • This increases the inductance (L) of the coil
  • The inductive reactance (XL = 2πfL) increases
  • More voltage drops across the inductor, leaving less for the bulb
  • As a result, the bulb's brightness decreases

Key parameters: AC source = 220V, 50Hz; Bulb resistance ≈ 31.4Ω (matched to initial XL)

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