Bar Magnet Field Simulation
Example 5.4
What is the magnitude of the equatorial and axial fields due to a bar magnet of length 5.0 cm at a distance of 50 cm from its mid-point? The magnetic moment of the bar magnet is 0.40 A m².
Equatorial field:
\[B_E = \frac{\mu_0 m}{4 \pi r^3} = \frac{10^{-7} \times 0.4}{(0.5)^3} = 3.2 \times 10^{-7} \, \text{T}\]
Axial field:
\[B_A = \frac{\mu_0 2m}{4 \pi r^3} = 6.4 \times 10^{-7} \, \text{T}\]
\[B_E = \frac{\mu_0 m}{4 \pi r^3} = \frac{10^{-7} \times 0.4}{(0.5)^3} = 3.2 \times 10^{-7} \, \text{T}\]
Axial field:
\[B_A = \frac{\mu_0 2m}{4 \pi r^3} = 6.4 \times 10^{-7} \, \text{T}\]
Interactive Simulation
Explore the magnetic fields around a bar magnet:
0.40 A·m²
0.50 m
0.05 m
Equatorial Field (BE)
3.20 × 10-7 T
Axial Field (BA)
6.40 × 10-7 T
Ratio (BA/BE)
2.00
