Electron Path in Magnetic Field
Example 4.3: Electron's Circular Motion
This simulation demonstrates an electron's circular path in a perpendicular magnetic field.
Electron speed (v):
3 × 10⁷ m/s
Magnetic field (B):
6 × 10⁻⁴ T
Path radius (r):
0 cm
Frequency (f):
0 Hz
Energy (E):
0 keV
Key Formulas
r = mv/(qB)
f = v/(2πr)
E = ½mv² (converted to keV)
Calculations
r = (9×10⁻³¹ kg × 3×10⁷ m/s) / (1.6×10⁻¹⁹ C × 6×10⁻⁴ T)
r = 26 cm
f = (3×10⁷ m/s) / (2π × 0.26 m) ≈ 2 MHz
E = ½ × 9×10⁻³¹ kg × (3×10⁷ m/s)² = 2.5 keV
